Solucionario Gratis Mecanica De Fluidos Y Maquinas Hidrahulicas Claudio Mataix

. sports denver co. epub mfmeand.rar colntre.php · solucionario gratis mecanica de fluidos y maquinas hidrahulicas claudio mataix.Q:

Modal view controller is not loaded

I have a modal view controller and I am trying to push a new view controller in it. The navigation bar is not showing up and the view is not loaded. How can I make the navigation bar appear and the view appear in the modal view controller? My code is as follows:
let nvc = ThirdVC()

let nvcTop = UINavigationController(rootViewController: nvc)

ThirdVC().show()

let afvc = UIApplication.shared.delegate as! AppDelegate

afvc.rootNavigationController!.present(nvcTop, animated: true, completion: nil)

A:

I’m not sure what your base code looks like, but you should consider having nvcTop be an instance property of the ThirdVC, and then calling present on nvcTop. Right now your calling a method on ThirdVC with no return value, but ThirdVC is the top level view controller, and must contain at least one view controller, so call present on your nvcTop, set up nvcTop like this:
let nvcTop = ThirdVC()
let nvcTop.navigationItem.title = «Navigation bar not showing up!»
nvcTop.navigationItem.leftBarButtonItem = UIBarButtonItem(title: «Done», style:.plain, target: nil, action: nil)

And then, when you are ready to present the view controller, call presentViewController with an argument like so:
afvc.rootNavigationController!.presentViewController(nvcTop, animated: true, completion: nil)

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A:

Para hacerlo, usando un poquito de PHP, podes utilizar una sintaxis como la que podes ver en el siguiente fragmento de código:

$p = implode(»
«, array_map(function($i){return»$i
«;}, explode(»
«, $data)));
$p = str_replace(«\r
«, «», $p);
$p = preg_replace(«!^[\t\s]+!», «», $p);

Lo que hace es que trabaja con los valores de entrada desde un array por un for, y añade un salto de línea a cada linea del array. Por cada iteración se guarda el fragmento dentro de una variable, la cual se utiliza para armar el sistema.
Entonces, el sistema recibe un string como el siguiente:

$sistema = ‘algo
esta
bien
y
algo
mal’;

Esto es usado, comprueba cada segmento del string:
$p = preg_replace(«!^[\t\s]+!», «», $sistema);

Si el segmento está vacío, muestra un mensaje, si no, reemplaza el primer caracter por un espacio.
Para comprobar si es bueno, o si es malo, buscas por alguna palabra, y haz un match al respecto.
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